If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2-1x-17=0
a = 2; b = -1; c = -17;
Δ = b2-4ac
Δ = -12-4·2·(-17)
Δ = 137
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{137}}{2*2}=\frac{1-\sqrt{137}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{137}}{2*2}=\frac{1+\sqrt{137}}{4} $
| 9z*15=7914 | | 9d+13=-5d+12 | | x5x−9=3x+3 | | 4j-3=7j+12 | | 27=6(x+3)+3x | | -6u+2(u-4)=8 | | 2a+9=12 | | 4=-2(x=4) | | (9z)(15)=7914 | | -2v+5(v+2)=25 | | 2n^2-12n=10=0 | | 10√b=4(√b+12) | | 3x+7=55x-13 | | 4m-27+3m=8 | | 3(2x+6)=2(6x-12) | | 15^x=200 | | 7x-36=-2(x-9) | | −6x2+12x=7 | | 390p=20 | | 180p=20 | | 1/8x+3/4=1/4 | | 2564-7x=1325 | | 3x-7=5×+13 | | 3(2x+10)=10x+4-2x | | 3(4x+5)-4(2x-3)=36 | | 14=3y=10y | | 12m+8−5m+2+m=6(m+1 | | |j|=13/4 | | 5+.5(12)=y | | 8(7m–2)=9.5m+1. | | x2+16x–36=0 | | x2+16x–36=0. |